(2xy-3y)dx+(x^2-3x)dy=0

解答

(2 x y - 3 y) d x + (x^{2} - 3 x) d y = 0

y = \frac{c _{1}}{x ^{2} - 3 x}

求解步骤

(2 x y - 3 y) d x + (x^{2} - 3 x) d y = 0

求解可分离方程:

y = \frac{c _{1}}{x ^{2} - 3 x}

y = \frac{c _{1}}{x ^{2} - 3 x}

sin (x) \cdot y^{^{'}} = x \cdot y

\frac{d y}{d x} = \frac{7 y ^{2}}{sec ( x )}

\frac{d y}{d x} + 3 x^{2} y = 3 x^{2}

\frac{d y}{d t} = - 6 y

\frac{d}{d x} (y^{2} \frac{1}{b ^{2}}) = 1