y^'+y/3 =3,y(-1)=0

Lösung

y^{^{'}} + \frac{y}{3} = 3, y (- 1) = 0

y = - 9 e^{\frac{- t - 1}{3}} + 9

Schritte zur Lösung

y^{'} (t) + \frac{y}{3} = 3

Solve separable ODE:

y = - 9 e^{\frac{- t - 1}{3}} + 9

y = - 9 e^{\frac{- t - 1}{3}} + 9

y^{^{'}} = y^{2} e^{- t}, y (0) = 0.5

y^{^{'}} = (y x^{2} + x^{2})^{2}

y^{^{'}} - 3 y = 0, y (0) = 1

\frac{d y}{d x} = \frac{x ^{3}}{( y + 2 ) ^{2}}, y (0) = - 1

x^{^{'}} = 4 + 2 x