What is the solution for y^'=cos(x)sec(y) ?

The solution for y^'=cos(x)sec(y) is y=arcsin(sin(x)+c_{1})+2pin,y=pi+arcsin(-sin(x)-c_{1})+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=cos(x)sec(y)

y^{^{'}} = cos (x) sec (y)

y = arcsin (sin (x) + c_{1}) + 2 πn, y = π + arcsin (- sin (x) - c_{1}) + 2 πn

Solution steps

y^{'} (x) = cos (x) sec (y)

Solve separable ODE:

y = arcsin (sin (x) + c_{1}) + 2 πn, y = π + arcsin (- sin (x) - c_{1}) + 2 πn

y = arcsin (sin (x) + c_{1}) + 2 πn, y = π + arcsin (- sin (x) - c_{1}) + 2 πn

What is the solution for y^'=cos(x)sec(y) ?
The solution for y^'=cos(x)sec(y) is y=arcsin(sin(x)+c_{1})+2pin,y=pi+arcsin(-sin(x)-c_{1})+2pin