y+5+(x-2)y^'=0

Lösung

y + 5 + (x - 2) y^{^{'}} = 0

y = \frac{c _{1}}{x - 2} - 5

Schritte zur Lösung

y + 5 + (x - 2) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x - 2} - 5

y = \frac{c _{1}}{x - 2} - 5

y^{^{'}} - x y^{2} = x

y^{^{'}} = - 5 y + 20

y^{^{'}} = 8 t cos^{2} (y), y (1) = \frac{3 π}{4}

y^{^{'}} = (\frac{1}{1 + x}) y

6 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = - 5