y^'=(x^2y^2)/(1+x^2)

Lösung

y^{^{'}} = \frac{x ^{2} y ^{2}}{1 + x ^{2}}

y = - \frac{1}{- arctan ( x ) + x + c _{1}}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{2} y ^{2}}{1 + x ^{2}}

Solve separable ODE:

y = - \frac{1}{- arctan ( x ) + x + c _{1}}

y = - \frac{1}{- arctan ( x ) + x + c _{1}}

\frac{d y}{d x} = 20 x sec (y)

y y^{^{'}} = x^{3}, y (0) = 3

\frac{d y}{d x} sin (y) + x cos (y) + x = 0

\frac{d y}{d t} + 2 y = - 1

y^{^{'}} = 1 - x - y + x y