yy^'=x^3,y(0)=3

Lösung

y y^{^{'}} = x^{3}, y (0) = 3

y = \frac{x ^{4}}{2} + 9

Schritte zur Lösung

y y^{'} (x) = x^{3}

Solve separable ODE:

y = \frac{x ^{4}}{2} + 9

y = \frac{x ^{4}}{2} + 9

\frac{d y}{d x} sin (y) + x cos (y) + x = 0

\frac{d y}{d t} + 2 y = - 1

y^{^{'}} = 1 - x - y + x y

\frac{d y}{d x} = 3 x^{5} y

\frac{d y}{d x} = - \frac{3}{4} x^{7} y^{8}