x^2y^'-y^2=0

Lösung

x^{2} y^{^{'}} - y^{2} = 0

y = - \frac{x}{- 1 + c _{1} x}

Schritte zur Lösung

x^{2} y^{'} (x) - y^{2} = 0

Solve separable ODE:

y = - \frac{x}{- 1 + c _{1} x}

y = - \frac{x}{- 1 + c _{1} x}

\frac{d x}{d t} = r (1 - \frac{x}{k})

y \cdot \frac{d y}{d x} + 2 x - 1 = 0

2 \frac{d y}{d x} = - 4 y + 5

\frac{d y}{d x} = x y, x (1) = 4

(x + 1) (t^{2} + 1) = t \frac{d x}{d t}