(t^2-26t+120)y^'=y

Lösung

(t^{2} - 26 t + 120) y^{^{'}} = y

y = \frac{c _{1} 14 t - 20}{14 t - 6}

Schritte zur Lösung

(t^{2} - 26 t + 120) y^{'} (t) = y

Solve separable ODE:

y = \frac{c _{1} 14 t - 20}{14 t - 6}

y = \frac{c _{1} 14 t - 20}{14 t - 6}

y^{^{'}} = \frac{( y - 2 ) ^{2}}{x ^{2} + 1}

\frac{d y}{y} = 34 y x^{16} d x

y^{^{'}} + \frac{y}{8 x} = 0, y (5) = e

\frac{( x + a ) d y}{d x - y} = b

e^{- y} cos (x) - \frac{d y}{d x} = 0