(dy)/(dt)=te^{t+y}

Lösung

\frac{d y}{d t} = t e^{t + y}

y = - ln (- e^{t} t + e^{t} - c_{1})

Schritte zur Lösung

\frac{d y}{d t} = t e^{t + y}

Solve separable ODE:

y = - ln (- e^{t} t + e^{t} - c_{1})

y = - ln (- e^{t} t + e^{t} - c_{1})

\frac{d x}{d y} = 0.8 (28 - x)

y^{^{'}} + x y^{^{'}} - 2 y = 0

(x + 1) \frac{d y}{d x} = - y + 20

y^{^{'}} = e^{x^{2}} y^{2} - 81

y y^{^{'}} + t = t y^{2}