y^'+xy^'-2y=0

Lösung

y^{^{'}} + x y^{^{'}} - 2 y = 0

y = e^{c_{1}} + 2 e^{c_{1}} x + e^{c_{1}} x^{2}

Schritte zur Lösung

y^{'} (x) + x y^{'} (x) - 2 y = 0

Solve separable ODE:

y = e^{c_{1}} + 2 e^{c_{1}} x + e^{c_{1}} x^{2}

y = e^{c_{1}} + 2 e^{c_{1}} x + e^{c_{1}} x^{2}

(x + 1) \frac{d y}{d x} = - y + 20

y^{^{'}} = e^{x^{2}} y^{2} - 81

y y^{^{'}} + t = t y^{2}

(6 + x^{8}) \frac{d y}{d x} = (\frac{x}{y})^{7}

5 y^{^{'}} = y cos (5 x), y (0) = 1