y^'-5x^3e^y=0

Lösung

y^{^{'}} - 5 x^{3} e^{y} = 0

y = - ln (- \frac{5 x ^{4}}{4} - c_{1})

Schritte zur Lösung

y^{'} (x) - 5 x^{3} e^{y} = 0

Solve separable ODE:

y = - ln (- \frac{5 x ^{4}}{4} - c_{1})

y = - ln (- \frac{5 x ^{4}}{4} - c_{1})

\frac{d y}{d x} = 1 y + y^{2}

y^{^{'}} = 0.5 (y e^{x})^{\frac{1}{3}}

y^{^{'}} y = 2 x + 1, y (0) = 1

ln (x) \cdot y^{^{'}} - \frac{2 y}{x} = 0

\frac{d y}{d t} = t e^{t + y}