dx+sin(t)xdt-sin(t)dt=0,x(pi/2)=-1

Lösung

d x + sin (t) x d t - sin (t) d t = 0, x (\frac{π}{2}) = - 1

t = arccos (ln (x - 1) - c_{1}) + 2 πn, t = - arccos (ln (x - 1) - c_{1}) + 2 πn

Schritte zur Lösung

d x + sin (t) x d t - sin (t) d t = 0

Solve separable ODE:

t = arccos (ln (x - 1) - c_{1}) + 2 πn, t = - arccos (ln (x - 1) - c_{1}) + 2 πn

t = arccos (ln (x - 1) - c_{1}) + 2 πn, t = - arccos (ln (x - 1) - c_{1}) + 2 πn

y^{^{'}} + tan (3 x) y = 0

y^{^{'}} = e^{4 y + 10 x}

e^{(2 x)} y^{2} y^{^{'}} = 1

\frac{d y}{d x} + \frac{3 y}{x} = \frac{3}{x}

\frac{d y}{y} = 3 x^{2} d x