y^'+tan(3x)y=0

Lösung

y^{^{'}} + tan (3 x) y = 0

y = c_{1} 3 cos (3 x)

Schritte zur Lösung

y^{'} (x) + tan (3 x) y = 0

Solve separable ODE:

y = c_{1} 3 cos (3 x)

y = c_{1} 3 cos (3 x)

y^{^{'}} = e^{4 y + 10 x}

e^{(2 x)} y^{2} y^{^{'}} = 1

\frac{d y}{d x} + \frac{3 y}{x} = \frac{3}{x}

\frac{d y}{y} = 3 x^{2} d x

x sin (x) y^{^{'}} - (sin (x) + x cos (x)) y = 0