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Frequently Asked Questions (FAQ)
What is the solution for y^{''}+2y^'=x^2+e^{-2x} ?
- The solution for y^{''}+2y^'=x^2+e^{-2x} is y=c_{1}+c_{2}e^{-2x}+(x^3)/6+(-x^2+x)/4-(e^{-2x}x)/2