What is the limit as x approaches-1 of (x^2-1)/(x+1) ?

The limit as x approaches-1 of (x^2-1)/(x+1) is -2

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limit as x approaches-1 of (x^2-1)/(x+1)

x \to - 1 lim (\frac{x ^{2} - 1}{x + 1})

- 2

Solution steps

x \to - 1 lim (\frac{x ^{2} - 1}{x + 1})

Simplify

\frac{x ^{2} - 1}{x + 1} : x - 1

= x \to - 1 lim (x - 1)

Plug in the value

x = - 1

= - 1 - 1

Simplify

= - 2

\frac{d ^{5}}{d x ^{5}} (\frac{1}{x ^{2}})

\int \frac{1}{s ^{3} - 1} d s

\frac{d}{d x} (x arctan (2 x) - \frac{1}{4} ln (1 + 4 x^{2}))

t an g e n t 9 x^{\frac{3}{5}} - 2 x^{\frac{6}{7}}, at x = 3

t an g e n t f (x) = tan (x), (\frac{3 π}{4}, - 1)

What is the limit as x approaches-1 of (x^2-1)/(x+1) ?
The limit as x approaches-1 of (x^2-1)/(x+1) is -2