(10x-1)y^'+10y=0

Lösung

(10 x - 1) y^{^{'}} + 10 y = 0

y = \frac{c _{1}}{10 x - 1}

Schritte zur Lösung

(10 x - 1) y^{'} (x) + 10 y = 0

Solve separable ODE:

y = \frac{c _{1}}{10 x - 1}

y = \frac{c _{1}}{10 x - 1}

y^{^{'}} = e^{2 y - x}, y (0) = - 1

y^{^{'}} \cdot y \cdot e^{x^{2}} - 2 x = 0

(x^{2}) d x + (2 y) d y = 0

\frac{d y}{d x} = \frac{x - 8}{y ^{3}}

y^{^{'}} = y^{2} (9 x + 5)