2yy^'=15t^2,y(0)=8

Lösung

2 y y^{^{'}} = 15 t^{2}, y (0) = 8

y = 5 t^{3} + 64

Schritte zur Lösung

2 y y^{'} (t) = 15 t^{2}

Solve separable ODE:

y = 5 t^{3} + 64

y = 5 t^{3} + 64

x y^{2} d x + e^{x} d y = 0, y = \frac{1}{2}

x y^{^{'}} = y, y (a) = b

\frac{d y}{d x} = 2 x (1 - y)

y^{^{'}} = e^{3 x - 2 y} + x^{2} e^{- 2 y}

\frac{d t}{d x} + \frac{3}{x} = - \frac{1}{x ^{2}}