xy^'-y=2

Lösung

x y^{^{'}} - y = 2

y = c_{1} x - 2

Schritte zur Lösung

x y^{'} (x) - y = 2

Solve separable ODE:

y = c_{1} x - 2

y = c_{1} x - 2

y^{^{'}} = - \frac{3 x ^{2}}{4 y}

y^{^{'}} = y cos (5 x), y (0) = 1

y^{^{'}} = - 2 - y + y^{2}

\frac{d y}{d t} = \frac{t ^{2}}{y}

y^{^{'}} = cos (x) (3 y - 1)