y^'=(x^2+1)/(2-y)

Lösung

y^{^{'}} = \frac{x ^{2} + 1}{2 - y}

y = - \frac{- 12 + 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}, y = - \frac{- 12 - 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{2} + 1}{2 - y}

Solve separable ODE:

y = - \frac{- 12 + 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}, y = - \frac{- 12 - 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}

y = - \frac{- 12 + 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}, y = - \frac{- 12 - 144 + 12 ( - c _{1} - 6 x - 2 x ^{3} )}{6}

y^{^{'}} = \frac{2 x + x y ^{2}}{4 y + y x ^{2}}

\frac{d p}{d t} = p (1 - p)

(1 + x^{2}) \frac{d y}{d x} = 1 + y^{2}

y^{^{'}} = y sec (x)

\frac{d y}{d x} = y + \frac{y}{x ln ( x )}