y^'+7y+5x=5x

Lösung

y^{^{'}} + 7 y + 5 x = 5 x

y = e^{- 7 x + c_{1}}

Schritte zur Lösung

y^{'} (x) + 7 y + 5 x = 5 x

Solve separable ODE:

y = e^{- 7 x + c_{1}}

y = e^{- 7 x + c_{1}}

y d x + 2 x d y = 0

3 \frac{d y}{d x} - y = 12 e^{- 5}

y e^{x} d y - (e^{- y} + e^{2 x - y}) d x = 0

y^{^{'}} = \frac{y ^{2}}{3 x}

\frac{d y}{d x} = \frac{8 ( 1 + x )}{x y}