We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the integral of 1/(x(x^2-16)^{3/2)} ?
- The integral of 1/(x(x^2-16)^{3/2)} is 1/64 (-arcsec(1/4 x)-4/((x^2-16)^{1/2)})+C