sum from n=1 to infinity of 9/n-9/(n+1)

Lösung

n = 1 \sum \infty \frac{9}{n} - \frac{9}{n + 1}

9

Schritte zur Lösung

n = 1 \sum \infty \frac{9}{n} - \frac{9}{n + 1}

Teleskopreihen-Test anwenden:

9

= 9

n = 1 \sum \infty \frac{6}{3 n ^{2} + 2}

n = 1 \sum \infty \frac{1}{n ^{2} + n + 3}

n = 1 \sum \infty 1 - \frac{1}{n}

n = 1 \sum \infty \frac{5}{n !}

n = 1 \sum \infty \frac{5}{4 ^{n}}