integral from 5 to 10 of (2.6)/t

Lösung

\int_{5}^{10} \frac{2.6}{t} d t

2.6 ln (2)

Dezimale

1.80218 \dots

Schritte zur Lösung

\int_{5}^{10} \frac{2.6}{t} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2.6 \cdot \int_{5}^{10} \frac{1}{t} d t

Nutze das gemeinsame Integral :

\int \frac{1}{t} d t = ln (∣ t ∣)

= 2.6 [ln ∣ t ∣]_{5}^{10}

Berechne die Grenzen:

ln (10) - ln (5)

= 2.6 (ln (10) - ln (5))

Vereinfache

= 2.6 ln (2)

\int_{1}^{\infty} \frac{k}{x ^{3}} d x

\int_{1}^{\infty} t^{2} e^{- t} d t

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (2 t) d t

\int_{- 2}^{3} y^{2} - y - 6 d y

\int_{0}^{2} 4 t^{2} + 9 t^{4} d t