integral from 2 to 5 of (x^3+x-4)

Lösung

\int_{2}^{5} (x^{3} + x - 4) d x

\frac{603}{4}

Dezimale

150.75

Schritte zur Lösung

\int_{2}^{5} x^{3} + x - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} x^{3} d x + \int_{2}^{5} x d x - \int_{2}^{5} 4 d x

\int_{2}^{5} x^{3} d x = \frac{609}{4}

\int_{2}^{5} x d x = \frac{21}{2}

\int_{2}^{5} 4 d x = 12

= \frac{609}{4} + \frac{21}{2} - 12

Vereinfache

\frac{609}{4} + \frac{21}{2} - 12 : \frac{603}{4}

= \frac{603}{4}

\int_{0}^{1} (a + x)^{2} - x^{2} d a

\int_{0}^{- 1} (x ln (x)) d x

\int_{c}^{d} x d x

\int_{1}^{4} \frac{1}{6} d x

\int_{0.5}^{1} 3 x^{4} + \frac{1}{2 x} - 5 d x