integral from-1 to 0 of 3x+3

Lösung

\int_{- 1}^{0} 3 x + 3 d x

\frac{3}{2}

Dezimale

1.5

Schritte zur Lösung

\int_{- 1}^{0} 3 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 3 x d x + \int_{- 1}^{0} 3 d x

\int_{- 1}^{0} 3 x d x = - \frac{3}{2}

\int_{- 1}^{0} 3 d x = 3

= - \frac{3}{2} + 3

Vereinfache

- \frac{3}{2} + 3 : \frac{3}{2}

= \frac{3}{2}

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