integral from 0 to 3 of |x^3-4x^2+3x|

Lösung

\int_{0}^{3} x^{3} - 4 x^{2} + 3 x d x

\frac{37}{12}

Dezimale

3.08333 \dots

Schritte zur Lösung

\int_{0}^{3} x^{3} - 4 x^{2} + 3 x d x

Entferne die Extremwerte

= \int_{0}^{1} x^{3} - 4 x^{2} + 3 x d x + \int_{1}^{3} - x^{3} + 4 x^{2} - 3 x d x

\int_{0}^{1} x^{3} - 4 x^{2} + 3 x d x = \frac{5}{12}

\int_{1}^{3} - x^{3} + 4 x^{2} - 3 x d x = \frac{8}{3}

= \frac{5}{12} + \frac{8}{3}

Vereinfache

\frac{5}{12} + \frac{8}{3} : \frac{37}{12}

= \frac{37}{12}

\int_{- 2}^{0} (x^{4} - 2 x) d x

\int_{0}^{60} x (\frac{1}{1800} x) d x

\int_{1}^{2} x 1 + 4 x^{2} d x

\int_{0}^{1} π d x

\int_{0}^{2} t^{3} \cdot 9 t^{4} + 1 d t