integral from 2 to 0 of sin(x)

Lösung

\int_{2}^{0} sin (x) d x

cos (2) - 1

Dezimale

- 1.41614 \dots

Schritte zur Lösung

\int_{2}^{0} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{2} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{0}^{2}

Berechne die Grenzen:

- cos (2) + 1

= - (- cos (2) + 1)

Vereinfache

= cos (2) - 1

\int_{4}^{5} \frac{2}{x ^{2} - 1} d x

\int_{- 1}^{0} (x^{2} - 2 x - \frac{1}{3}) d x

\int_{2}^{3} x^{4} ln (x) d x

\int_{0}^{\infty} \frac{1}{e ^{x} + 3} d x

\int_{0}^{2} \frac{x ^{2}}{16} d x