integral of+8x-1

Lösung

\int + 8 x - 1 d x

4 x^{2} - x + C

Schritte zur Lösung

\int 8 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x d x - \int 1 d x

\int 8 x d x = 4 x^{2}

\int 1 d x = x

= 4 x^{2} - x

Füge eine Konstante zur Lösung hinzu

= 4 x^{2} - x + C

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