What is the integral of tsqrt(t+2) ?

The integral of tsqrt(t+2) is 2/5 (t+2)^{5/2}-4/3 (t+2)^{3/2}+C

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integral of tsqrt(t+2)

\int t t + 2 d t

\frac{2}{5} (t + 2)^{\frac{5}{2}} - \frac{4}{3} (t + 2)^{\frac{3}{2}} + C

Solution steps

\int t t + 2 d t

Apply u-substitution

= \int (u - 2) u d u

Expand

(u - 2) u : u^{\frac{3}{2}} - 2 u

= \int u^{\frac{3}{2}} - 2 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u - \int 2 u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 2 u d u = \frac{4}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} - \frac{4}{3} u^{\frac{3}{2}}

Substitute back

u = t + 2

= \frac{2}{5} (t + 2)^{\frac{5}{2}} - \frac{4}{3} (t + 2)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (t + 2)^{\frac{5}{2}} - \frac{4}{3} (t + 2)^{\frac{3}{2}} + C

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What is the integral of tsqrt(t+2) ?
The integral of tsqrt(t+2) is 2/5 (t+2)^{5/2}-4/3 (t+2)^{3/2}+C