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Frequently Asked Questions (FAQ)
What is the solution for y^{''}-3y^'+2y=0,y(0)=1,y^'(0)=-7/3 ?
- The solution for y^{''}-3y^'+2y=0,y(0)=1,y^'(0)=-7/3 is y=(1-13/3)e^{2t}+13/3 e^t