integral of (8x^5-3x^2-2x+5)

Lösung

\int (8 x^{5} - 3 x^{2} - 2 x + 5) d x

\frac{4 x ^{6}}{3} - x^{3} - x^{2} + 5 x + C

Schritte zur Lösung

\int 8 x^{5} - 3 x^{2} - 2 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{5} d x - \int 3 x^{2} d x - \int 2 x d x + \int 5 d x

\int 8 x^{5} d x = \frac{4 x ^{6}}{3}

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

\int 5 d x = 5 x

= \frac{4 x ^{6}}{3} - x^{3} - x^{2} + 5 x

Füge eine Konstante zur Lösung hinzu

= \frac{4 x ^{6}}{3} - x^{3} - x^{2} + 5 x + C

\int \frac{2}{x ^{3} - x ^{2}} d x

\int \frac{1}{( 2 x + 3 ) ( x - 1 )} d x

\int 3 x^{2} - 2 x + 1 d x

\int \frac{1}{225 - x ^{2}} d x

\int 3 X^{2} - 6 X + 8 d X