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Popular Calculus >

y^'=x+4

Solution

y^{^{'}} = x + 4

Solution

y = \frac{x ^{2}}{2} + 4 x + c_{1}

Solution steps

y^{'} (x) = x + 4

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x + 4 d x

\int x + 4 d x = \frac{x ^{2}}{2} + 4 x + c_{1}

y = \frac{x ^{2}}{2} + 4 x + c_{1}

Graph

Popular Examples

f^'(x)=(32x^3)/(2x^4+5)

f^'(x)=3x^2+3x-2.25

y^'=-5 x/2-2/5 x

(x(1-x)y^{''}-5)/(2y^'-y)=0

y^{''}-4y+4y=2e^2x

Frequently Asked Questions (FAQ)

What is the solution for y^'=x+4 ?
The solution for y^'=x+4 is y=(x^2)/2+4x+c_{1}