What is the solution for f^'(x)=(32x^3)/(2x^4+5) ?

The solution for f^'(x)=(32x^3)/(2x^4+5) is f(x)=4ln(2x^4+5)+c_{1}

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f^'(x)=(32x^3)/(2x^4+5)

f^{^{'}} (x) = \frac{32 x ^{3}}{2 x ^{4} + 5}

f (x) = 4 ln (2 x^{4} + 5) + c_{1}

Solution steps

f^{'} (x) = \frac{32 x ^{3}}{2 x ^{4} + 5}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{32 x ^{3}}{2 x ^{4} + 5} d x

\int \frac{32 x ^{3}}{2 x ^{4} + 5} d x = 4 ln (2 x^{4} + 5) + c_{1}

f (x) = 4 ln (2 x^{4} + 5) + c_{1}

What is the solution for f^'(x)=(32x^3)/(2x^4+5) ?
The solution for f^'(x)=(32x^3)/(2x^4+5) is f(x)=4ln(2x^4+5)+c_{1}