y-6y^'+13y=0,y(0)=e^3xcos(2x)

Lösung

y - 6 y^{^{'}} + 13 y = 0, y (0) = e^{3} x cos (2 x)

y = e^{\frac{7 x + c _{1}}{3}}

Schritte zur Lösung

y - 6 y^{'} (x) + 13 y = 0

Solve separable ODE:

y = e^{\frac{7 x + c _{1}}{3}}

y = e^{\frac{7 x + c _{1}}{3}}

\frac{y ^{^{'}} + y}{x} = 0

2 y^{^{'}} + y + 1 = 0

sin (x) y^{^{'}} = y cos (x) + 2 cos (x)

\frac{y ^{^{'}}}{y} = e^{2 x^{2} + 5}

3 x y^{^{'}} - y = 0