(y^'+y)/x =0

Lösung

\frac{y ^{^{'}} + y}{x} = 0

y = e^{- x + c_{1}}

Schritte zur Lösung

\frac{y ^{'} ( x ) + y}{x} = 0

Solve separable ODE:

y = e^{- x + c_{1}}

y = e^{- x + c_{1}}

2 y^{^{'}} + y + 1 = 0

sin (x) y^{^{'}} = y cos (x) + 2 cos (x)

\frac{y ^{^{'}}}{y} = e^{2 x^{2} + 5}

3 x y^{^{'}} - y = 0

(1 + x^{2}) y^{^{'}} + y = - 1