(d^2-4)y=3e^2x-4e^{-2}x

解答

(d^{2} - 4) y = 3 e^{2} x - 4 e^{- 2} x

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{( 3 e ^{4} - 4 ) x}{4 e ^{2}}

求解步骤

(d^{2} - 4) y = 3 e^{2} x - 4 e^{- 2} x

求解线性方程:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{( 3 e ^{4} - 4 ) x}{4 e ^{2}}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{( 3 e ^{4} - 4 ) x}{4 e ^{2}}

y^{^{''}} + 4 y = e^{2} t

(d^{2} - 3 d + 2) \cdot y = e^{2 x}

(d^{2} - 4) \cdot y = x \cdot sinh (x)

(d^{2} - 2 d + 3) \cdot y = cos (x) + x^{2}

(d^{3} + 3 d^{2} + 2 d) y = x