(d^2-d-2)y=6e^{(-t)/2}

Lösung

(d^{2} - d - 2) y = 6 e^{\frac{- t}{2}}

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

Schritte zur Lösung

(d^{2} - d - 2) y = 6 e^{\frac{- t}{2}}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

so l v e f or d, d (q) = - 0.4 q + 23

(d^{2} + 4) y = 4 sin^{2} (x)

(d^{2} - 4) y = 3 e^{2} x - 4 e^{- 2} x

y^{^{''}} + 4 y = e^{2} t

(d^{2} - 3 d + 2) \cdot y = e^{2 x}