What is the integral of e^{6x} ?

The integral of e^{6x} is 1/6 e^{6x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of e^{6x}

integral

e^{6 x}

\frac{1}{6} e^{6 x} + C

Solution steps

\int e^{6 x} d x

Apply u-substitution

= \int e^{u} \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{6} e^{u}

Substitute back

u = 6 x

= \frac{1}{6} e^{6 x}

Add a constant to the solution

= \frac{1}{6} e^{6 x} + C

in t e g r a l \frac{sin ^{2} ( x ) tan ^{2} ( x )}{2}

in t e g r a l \frac{x}{x - 1}

in t e g r a l \frac{ln ( x )}{( 1 + 2 x ) ^{2}}

in t e g r a l a + 3 c - 2 d

in t e g r a l (1 - 0.1 x)^{- 2}