What is the integral of 1/(x^2+2) ?

The integral of 1/(x^2+2) is 1/(sqrt(2))arctan(x/(sqrt(2)))+C

Popular >

integral of 1/(x^2+2)

integral

\frac{1}{x ^{2} + 2}

\frac{1}{2} arctan (\frac{x}{2}) + C

Solution steps

\int \frac{1}{x ^{2} + 2} d x

Apply Integral Substitution

= \int \frac{1}{2 ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= \frac{1}{2} arctan (u)

Substitute back

u = \frac{x}{2}

= \frac{1}{2} arctan (\frac{x}{2})

Add a constant to the solution

= \frac{1}{2} arctan (\frac{x}{2}) + C

(x + 2)^{3}

\frac{( 1 + e ^{- x} )}{x}

\frac{e ^{2 x}}{x}

\frac{1}{( x + 1 ) ^{5}}

e^{1 + x}

What is the integral of 1/(x^2+2) ?
The integral of 1/(x^2+2) is 1/(sqrt(2))arctan(x/(sqrt(2)))+C