What is the derivative of tan(e^s)inx^2 ?

The derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s

What is the first derivative of tan(e^s)inx^2 ?

The first derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s

derivative of

tan (e^{s}) in x^{2}

in x^{2} sec^{2} (e^{s}) e^{s}

Solution steps

\frac{d}{d s} (tan (e^{s}) in x^{2})

Treat

i, n, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= in x^{2} \frac{d}{d s} (tan (e^{s}))

Apply the chain rule:

sec^{2} (e^{s}) \frac{d}{d s} (e^{s})

= sec^{2} (e^{s}) \frac{d}{d s} (e^{s})

\frac{d}{d s} (e^{s}) = e^{s}

= in x^{2} sec^{2} (e^{s}) e^{s}

d er i v a t i v e (1 + x)^{2 y + 1}

d er i v a t i v e y = (sin (x))^{5}

d er i v a t i v e 2 - cos^{2} (x)

d er i v a t i v e \frac{tanh ( 4 x + 1 )}{5}

\frac{d}{d x} \frac{1}{( x + { n } ) \cdot x}

What is the derivative of tan(e^s)inx^2 ?
The derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s
What is the first derivative of tan(e^s)inx^2 ?
The first derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s