What is the derivative of (1+x)^{2y+1} ?

The derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}

What is the first derivative of (1+x)^{2y+1} ?

The first derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}

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derivative of

(1 + x)^{2 y + 1}

(2 y + 1) (1 + x)^{2 y}

Solution steps

\frac{d}{d x} ((1 + x)^{2 y + 1})

Treat

y

as a constant

Apply the chain rule:

(1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

= (1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= (1 + x)^{2 y} (2 y + 1) \cdot 1

Simplify

= (2 y + 1) (1 + x)^{2 y}

d er i v a t i v e y = (sin (x))^{5}

d er i v a t i v e 2 - cos^{2} (x)

d er i v a t i v e \frac{tanh ( 4 x + 1 )}{5}

\frac{d}{d x} \frac{1}{( x + { n } ) \cdot x}

d er i v a t i v e (k + 2 l)^{\frac{1}{3}}

What is the derivative of (1+x)^{2y+1} ?
The derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}
What is the first derivative of (1+x)^{2y+1} ?
The first derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}