derivative (1+x)^{2y+1}

解答

导数

(1 + x)^{2 y + 1}

(2 y + 1) (1 + x)^{2 y}

求解步骤

\frac{d}{d x} ((1 + x)^{2 y + 1})

将

y

视为常数

使用连锁律:

(1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

= (1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= (1 + x)^{2 y} (2 y + 1) \cdot 1

化简

= (2 y + 1) (1 + x)^{2 y}

d er i v a t i v e y = (sin (x))^{5}

d er i v a t i v e 2 - cos^{2} (x)

d er i v a t i v e \frac{tanh ( 4 x + 1 )}{5}

\frac{d}{d x} \frac{1}{( x + { n } ) \cdot x}

d er i v a t i v e (k + 2 l)^{\frac{1}{3}}