What is the derivative of f(x)=(x+sin(x))^2 ?

The derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))

What is the first derivative of f(x)=(x+sin(x))^2 ?

The first derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))

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derivative of

f (x) = (x + sin (x))^{2}

2 (x + sin (x)) (1 + cos (x))

Solution steps

\frac{d}{d x} ((x + sin (x))^{2})

Apply the chain rule:

2 (x + sin (x)) \frac{d}{d x} (x + sin (x))

= 2 (x + sin (x)) \frac{d}{d x} (x + sin (x))

\frac{d}{d x} (x + sin (x)) = 1 + cos (x)

= 2 (x + sin (x)) (1 + cos (x))

d er i v a t i v e \frac{2000}{x}

d er i v a t i v e 4 x^{3} - x^{2} + 1^{2}

d er i v a t i v e \frac{t ^{2}}{20} + \frac{t}{5}

d er i v a t i v e \frac{1}{ln ( 1 + 3 x )}

d er i v a t i v e lo g_{10} (tan (\frac{a}{2}))

What is the derivative of f(x)=(x+sin(x))^2 ?
The derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))
What is the first derivative of f(x)=(x+sin(x))^2 ?
The first derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))