What is the derivative of y=((x^5+x^2))/((x^3+1)) ?

The derivative of y=((x^5+x^2))/((x^3+1)) is 2x

What is the first derivative of y=((x^5+x^2))/((x^3+1)) ?

The first derivative of y=((x^5+x^2))/((x^3+1)) is 2x

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derivative of

y = \frac{( x ^{5} + x ^{2} )}{( x ^{3} + 1 )}

2 x

Solution steps

\frac{d}{d x} (\frac{x ^{5} + x ^{2}}{x ^{3} + 1})

Simplify

\frac{x ^{5} + x ^{2}}{x ^{3} + 1} : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

\frac{d}{d t} (65 + 2 t - 3 t^{2})

d er i v a t i v e - 2 ln (x)

d er i v a t i v e f (x) = (x + sin (x))^{2}

d er i v a t i v e \frac{2000}{x}

d er i v a t i v e 4 x^{3} - x^{2} + 1^{2}

What is the derivative of y=((x^5+x^2))/((x^3+1)) ?
The derivative of y=((x^5+x^2))/((x^3+1)) is 2x
What is the first derivative of y=((x^5+x^2))/((x^3+1)) ?
The first derivative of y=((x^5+x^2))/((x^3+1)) is 2x