derivative (t^3)/3+(t^2)/2+t-1

Lösung

ableitung von

\frac{t ^{3}}{3} + \frac{t ^{2}}{2} + t - 1

t^{2} + t + 1

Schritte zur Lösung

\frac{d}{d t} (\frac{t ^{3}}{3} + \frac{t ^{2}}{2} + t - 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{t ^{3}}{3}) + \frac{d}{d t} (\frac{t ^{2}}{2}) + \frac{d t}{d t} - \frac{d}{d t} (1)

\frac{d}{d t} (\frac{t ^{3}}{3}) = t^{2}

\frac{d}{d t} (\frac{t ^{2}}{2}) = t

\frac{d t}{d t} = 1

\frac{d}{d t} (1) = 0

= t^{2} + t + 1 - 0

Vereinfache

= t^{2} + t + 1

d er i v a t i v e 6^{x + 2}

d er i v a t i v e 10 y^{4}

d er i v a t i v e \frac{x ^{2} + 3 x + 5}{x ^{2} - 1}

d er i v a t i v e \frac{( x - 1 )}{( 2 x ^{2} )}

d er i v a t i v e (4 x^{5} + 1)^{3}