What is the derivative of y=(3+2x^2)^4 ?

The derivative of y=(3+2x^2)^4 is 16x(3+2x^2)^3

What is the first derivative of y=(3+2x^2)^4 ?

The first derivative of y=(3+2x^2)^4 is 16x(3+2x^2)^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative

16 x (3 + 2 x^{2})^{3}

Solution steps

\frac{d}{d x} ((3 + 2 x^{2})^{4})

Apply the chain rule:

4 (3 + 2 x^{2})^{3} \frac{d}{d x} (3 + 2 x^{2})

= 4 (3 + 2 x^{2})^{3} \frac{d}{d x} (3 + 2 x^{2})

\frac{d}{d x} (3 + 2 x^{2}) = 4 x

= 4 (3 + 2 x^{2})^{3} \cdot 4 x

Simplify

= 16 x (3 + 2 x^{2})^{3}

What is the derivative of y=(3+2x^2)^4 ?
The derivative of y=(3+2x^2)^4 is 16x(3+2x^2)^3
What is the first derivative of y=(3+2x^2)^4 ?
The first derivative of y=(3+2x^2)^4 is 16x(3+2x^2)^3