What is the derivative of (x^{-1})/2 ?

The derivative of (x^{-1})/2 is -1/(2x^2)

What is the first derivative of (x^{-1})/2 ?

The first derivative of (x^{-1})/2 is -1/(2x^2)

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derivative of

\frac{x ^{- 1}}{2}

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{- 1}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

\frac{( 2 x ^{2} - 4 )}{( 3 x ^{2} + 7 )}

\frac{t ^{3}}{6}

\frac{1}{x ^{2} + y ^{2}}

y = x^{5} + x^{3} - x + 10

4 x^{2} - 5 x - 1

What is the derivative of (x^{-1})/2 ?
The derivative of (x^{-1})/2 is -1/(2x^2)
What is the first derivative of (x^{-1})/2 ?
The first derivative of (x^{-1})/2 is -1/(2x^2)