What is the derivative of 2sin(3x-2) ?

The derivative of 2sin(3x-2) is 6cos(3x-2)

What is the first derivative of 2sin(3x-2) ?

The first derivative of 2sin(3x-2) is 6cos(3x-2)

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derivative of

2 sin (3 x - 2)

6 cos (3 x - 2)

Solution steps

\frac{d}{d x} (2 sin (3 x - 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (3 x - 2))

Apply the chain rule:

cos (3 x - 2) \frac{d}{d x} (3 x - 2)

= cos (3 x - 2) \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= 2 cos (3 x - 2) \cdot 3

Simplify

= 6 cos (3 x - 2)

x^{12} ln ∣ x ∣

y = (sin (x + y))^{2}

\frac{- x}{2}

2 - cos^{3} (x)

60 q - 2 q^{2}

What is the derivative of 2sin(3x-2) ?
The derivative of 2sin(3x-2) is 6cos(3x-2)
What is the first derivative of 2sin(3x-2) ?
The first derivative of 2sin(3x-2) is 6cos(3x-2)