What is the derivative of-9sin^3(x) ?

The derivative of-9sin^3(x) is -27sin^2(x)cos(x)

What is the first derivative of-9sin^3(x) ?

The first derivative of-9sin^3(x) is -27sin^2(x)cos(x)

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derivative of

- 9 sin^{3} (x)

- 27 sin^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (- 9 sin^{3} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (sin^{3} (x))

Apply the chain rule:

3 (sin (x))^{2} \frac{d}{d x} (sin (x))

= 3 (sin (x))^{2} \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= - 9 \cdot 3 (sin (x))^{2} cos (x)

Simplify

= - 27 sin^{2} (x) cos (x)

\frac{d}{dd} (ln (\frac{ln ( 8 l )}{d}) - 1)

12 x - 4

3 tan (x) - 4 cot (x_{7}) x^{2}

2 sin (3 x - 2)

x^{12} ln ∣ x ∣

What is the derivative of-9sin^3(x) ?
The derivative of-9sin^3(x) is -27sin^2(x)cos(x)
What is the first derivative of-9sin^3(x) ?
The first derivative of-9sin^3(x) is -27sin^2(x)cos(x)