integral from 0 to pi/(24) of cos(6x)

Lösung

\int_{0}^{\frac{π}{24}} cos (6 x) d x

\frac{1}{6 2}

Dezimale

0.11785 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{24}} cos (6 x) d x

Wende U-Substitution an

= \int_{0}^{\frac{π}{4}} cos (u) \frac{1}{6} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int_{0}^{\frac{π}{4}} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{6} [sin (u)]_{0}^{\frac{π}{4}}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{6} \cdot \frac{1}{2}

Vereinfache

= \frac{1}{6 2}

\frac{\partial}{\partial z} (3 y e^{- z})

\frac{d y}{d x} = (\frac{( 2 y + 3 )}{4 x + 5})^{2}

\frac{d}{d x} (ln (\frac{3 x + 1}{x ^{2} - 2}))

d er i v a t i v e 3 x e^{x} csc (x)

x \to 0 lim (sin^{2} (x) (\frac{1}{x}))