(dy)/(dx)=(((2y+3))/(4x+5))^2

解

\frac{d y}{d x} = (\frac{( 2 y + 3 )}{4 x + 5})^{2}

y = - \frac{4 x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{24 c _{1} x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{30 c _{1}}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{7}{2 ( - 1 + 16 c _{1} x + 20 c _{1} )}

解答ステップ

\frac{d y}{d x} = (\frac{( 2 y + 3 )}{4 x + 5})^{2}

分離可能 ODE を解く:

y = - \frac{4 x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{24 c _{1} x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{30 c _{1}}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{7}{2 ( - 1 + 16 c _{1} x + 20 c _{1} )}

y = - \frac{4 x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{24 c _{1} x}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{30 c _{1}}{- 1 + 16 c _{1} x + 20 c _{1}} - \frac{7}{2 ( - 1 + 16 c _{1} x + 20 c _{1} )}